ABCD is a parallelogram. Point P on AB divides it in the ratio AP : PB = 3 : 2, and point Q on CD divides it in the ratio CQ : QD = 7 : 3. Let R be the intersection of PQ and AC. Then, find AR:AC.

Can anyone help here?

A square can be used; it's a parallelogram as well.

This one's for Alan or heureka...

Here is the pic

The similar triangles are shown.

So the answer is easy to find.

https://www.geogebra.org/classic/v28ktqng

Hi, Melody! Please correct your diagram; CQ = 7 and QD = 3

Thanks!

AR:AC = 6 / 13

I used 10 cm square and the result is the same as Melody's

Ok I think it is fixed.