ABCD is a parallelogram. Point P on AB divides it in the ratio AP : PB = 3 : 2, and point Q on CD divides it in the ratio CQ : QD = 7 : 3. Let R be the intersection of PQ and AC. Then, find AR:AC.
Can anyone help here?
A square can be used; it's a parallelogram as well.
This one's for Alan or heureka...
Here is the pic
The similar triangles are shown.
So the answer is easy to find.
https://www.geogebra.org/classic/v28ktqng
Hi, Melody! Please correct your diagram; CQ = 7 and QD = 3
Thanks!
AR:AC = 6 / 13
I used 10 cm square and the result is the same as Melody's
Ok I think it is fixed.
