A 1321.9 kg car rounds a circular turn of radius 21.9 m. If the road is flat and the coefficient of static friction between the tires and the road is 0.56, how fast can the car go without skidding?
The centripetal force required to keep the car from skidding is given by
F=mv2r
where m is the mass of the car, v is it's speed and r is the curve radius.
The frictional force is
F=μmg
where μ is the coefficient of friction and g is gravitational acceleration.
So equating these two forces we have:
v2r=μgv=√μgr
I'll let you put in the numbers.
The centripetal force required to keep the car from skidding is given by
F=mv2r
where m is the mass of the car, v is it's speed and r is the curve radius.
The frictional force is
F=μmg
where μ is the coefficient of friction and g is gravitational acceleration.
So equating these two forces we have:
v2r=μgv=√μgr
I'll let you put in the numbers.