+0

# Substitution method

0
230
3

Can someone explain substitution method when there are more than two parts?

ie) 9m - 2n - 42 = 0 and 5m - 2n - 26 = 0

Guest Apr 8, 2017

#1
+7203
+2

Can someone explain substitution method when there are more than two parts?
ie)

$$9m - 2n - 42 = 0$$

and

5m - 2n - 26 = 0

$$9m - 2n - 42 = 0 \\m= \color{red}\frac{2n+42}{9}$$

$$5m - 2n - 26 = 0\\5({\color{red}\frac{2n+42}{9}})-2n-26=0\\10n+210-18n-234=0\\-8n=24\\{\color{blue}n=-3}$$         [ substitute  $$m=\color{red}\frac{2n+42}{9}$$

$$9m - 2n - 42 = 0 \\9m-2(-3)-42=0\\9m=42-6\\m= \frac{36}{9}\\\color{blue}m=4$$

!

asinus  Apr 8, 2017
edited by asinus  Apr 8, 2017
Sort:

#1
+7203
+2

Can someone explain substitution method when there are more than two parts?
ie)

$$9m - 2n - 42 = 0$$

and

5m - 2n - 26 = 0

$$9m - 2n - 42 = 0 \\m= \color{red}\frac{2n+42}{9}$$

$$5m - 2n - 26 = 0\\5({\color{red}\frac{2n+42}{9}})-2n-26=0\\10n+210-18n-234=0\\-8n=24\\{\color{blue}n=-3}$$         [ substitute  $$m=\color{red}\frac{2n+42}{9}$$

$$9m - 2n - 42 = 0 \\9m-2(-3)-42=0\\9m=42-6\\m= \frac{36}{9}\\\color{blue}m=4$$

!

asinus  Apr 8, 2017
edited by asinus  Apr 8, 2017

### 9 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details