+15 Deleted - go an abuse someone elses site - Melody.
2. Suppose I have a bag with 12 slips of paper in it. Some of the slips have a 2 on them, and the rest have a 7 on them. If the expected value of the number shown on a slip randomly drawn from the bag is 3.25, then how many slips have a 2?
3. I have 5 marbles numbered 1 through 5 in a bag. Suppose I take out two different balls at random. What is the expected value of the sum of the numbers on the marbles?
4. Two standard six-faced dice are rolled. Cara scores x points if the sum of the numbers rolled is greater than or equal to their product, otherwise Jeremy scores one point. What should be the value of x to make the game fair?
5. An art starts walking from the origin. During each second, it has an equal chance of moving 1 inch right, 2 inches up, 3 inches left, or 4 inches down. What is the ant's expected location after 5 seconds if it starts at the origin?
6. A player chooses one of the numbers 1 through 4. After the choice has been made, two regular four-sided (tetrahedral) dice are rolled, with the sides of the dice numbered 1 through 4. If the number chosen appears on the bottom of exactly one die after it is rolled, then the player wins $1. If the number chosen appears on the bottom of both of the dice, then the player wins $2. If the number chosen does not appear on the bottom of either of the dice, the player loses $1. What is the expected return to the player, in dollars, for one roll of the dice?
deleted
+129852 2. Suppose I have a bag with 12 slips of paper in it. Some of the slips have a 2 on them, and the rest have a 7 on them. If the expected value of the number shown on a slip randomly drawn from the bag is 3.25, then how many slips have a 2?
Let N be the number that have a 2 on them.....then 12- N have a (7)
So we have that
(2)(N/12) + (7)(12 - N)/12 = 3.25 multiply through by 12
2N + 7(12 - N) = 39
2N + 84 - 7N = 39 subtract 84 from both sides
-5N = -45 divide both sides by -5
N = 9 = the number of slips with "2" on them
+129852 3. I have 5 marbles numbered 1 through 5 in a bag. Suppose I take out two different balls at random. What is the expected value of the sum of the numbers on the marbles?
We have P(5,2) = 20 possible ways to select the marbles
(1,2) (2,3) (3,4) (4,5)
(2,1) (3,2) (4,3) (5,4)
(1,3) (2,4) (3,5)
(3,1) (4,2) (5,3)
(1,4) (2,5)
(4,1) (5,2)
(1,5)
(5,1)
So the expected value of the sum is
3(2/20) + 4(2/20) + 5(4/20) + 6(4/20) + 7(4/20) + 8(2/20) + 9(2/20) = 6
CORRECTED ANSWER....THANKS TO THE GUEST FOR POINTING OUT MY LOGIC FLAW !!!!
+129852 5. An art starts walking from the origin. During each second, it has an equal chance of moving 1 inch right, 2 inches up, 3 inches left, or 4 inches down. What is the ant's expected location after 5 seconds if it starts at the origin?
Not totally sure about this.....but....after one second.....the expected position of the ant can be found as
[ 1(.25) - 3(.25) , 2(.25) - 4(.25) ] = [ -.5, -.5 ]
So....each second, the ant is expected to move 1/2 unit to the left and 1/2 unit down
So....after 5 seconds the expected location is 5 [ -.5, -.5 ] = (-2.5, -2.5)
+118673 Jerryjing2006 - You are a lazy cheating child who wants all your homework done for you.
Why do you persist in fascilitating cheating Chris.
+15 I'm sorry, but I think you've misunderstood me. These are my friends HW answers and he has asked me for his help. I have already completed all of his HW to the best of my ability. But I've posted these questions to further my knowledge on these topics and also help out a friend. I hope you understand!
+129852 4. Two standard six-faced dice are rolled. Cara scores x points if the sum of the numbers rolled is greater than or equal to their product, otherwise Jeremy scores one point. What should be the value of x to make the game fair?
Here is a table comparing sums and products
1 2 3 4 5 6
1 G G G G G G
2 G E L L L L
3 G L L L L L
4 G L L L L L
5 G L L L L L
6 G L L L L L
Cara has a (12/36) = (1/3) chance of having a greater or equal sum to a respective product
Jeremy has a (2/3) chance = twice Cara's chance
So
1 (2/3) = x (1/3)
(2/3) = (1/3) x divide both sides by (1/3)
(2/3) / (1/3) = x
(2/1) = x = 2 ⇒ Cara should get 2 points for a winning turn to make the game fair
+73 6. A player chooses one of the numbers 1 through 4. After the choice has been made, two regular four-sided (tetrahedral) dice are rolled, with the sides of the dice numbered 1 through 4. If the number chosen appears on the bottom of exactly one die after it has been rolled, then the player wins 1 dollar. If the number chosen appears on the bottom of both of the dice, then the player wins 2 dollars. If the number chosen does not appear on the bottom of either of the dice, the player loses 1 dollar. What is the expected return to the player, in dollars, for one roll of the dice?
--7H3_5H4D0W
