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avatar+1342 

 

How can I  double  the number line to use a 2000 km= 1 cm ? do i still cound by 1's or 2's , im not exactly sure?

 Sep 25, 2019
 #1
avatar+1342 
0

As your typing your response, I was wondering, where can i findinformation about how far from the sun is voyager 1 and 2 as of january 2,2009 , in meters? I cant find any information on it. Thank you, sorry I know it isnt math related but I cant find any info.

 Sep 25, 2019
edited by jjennylove  Sep 25, 2019
 #2
avatar+2230 
+3

This method is inaccurate.

 

Find the current speed of voyager 1 and 2. (google)

 

Find the current distance right now (google)

 

Now, find the amount of time that has elapsed between Janurary 2, 2009 and right now.

 

 

Then do some maths

 

Hint: Take the elapsed time, multiply by the speed, and the subtract that from the current distance

CalculatorUser  Sep 25, 2019
edited by CalculatorUser  Sep 25, 2019
edited by CalculatorUser  Sep 25, 2019
edited by CalculatorUser  Sep 25, 2019
 #3
avatar+2230 
+3

Sorry, my above answer is inaccurate, not necessarily incorrect.

 

Time is constantly moving forward, by 1 second each second laugh


So the distance is ever changing if you used my method above.

 

 

 

Easier method:

 

Find when Voyager 1 and 2 were launched. (google)

 

Find speed (google)

 

Fond elapsed time between initial launch and 2009 januarary 2

 

Then Mulitply elapse time and speed, done.

CalculatorUser  Sep 25, 2019
 #4
avatar+1342 
0

Ill check it out, thank you for yuor help! smiley

jjennylove  Sep 26, 2019
edited by jjennylove  Sep 26, 2019
 #5
avatar+104712 
+3

From Yahoo ( so....I can't vouch for the reliability)

 

At 0h UT (Greenwich time) on 2nd January 2009, Voyager 1 was 108.547628513 AU from the Sun. This is 16,238,494,019 km or 10,090,132,389 miles.

 

Also.....

 

From, Quora......as of Dec 1, 2017  .....Voyager 2 was traveling at about 34,390 mph= 55,345 km per hour.....it was slightly decelerating all the time 

 

Asuuming that the rate of deceleration is negligible.....there were  11,459 days   between its launch date of 8/20/77 and  01/02/2009

 

This is 275,016 hrs

 

So....from the Earth the (rough)  distance traveled (in meters)  =

 

275,016 hrs * (55,345 * 1000)m  =  15,220,760,520,000 m

 

And the distance from the Earth to the Sun (on average) is ≈  149,668,992,000 m

 

So.....on Jan 2,2009......Voyager 2 was about   15,370,429,512,000 m from the Sun

 

 

cool cool cool

 Sep 26, 2019
edited by CPhill  Sep 26, 2019
 #6
avatar+2230 
+2

Yes, CPhill calculated it!

 

Why is the universe so big, but small at the same time.

CalculatorUser  Sep 26, 2019
edited by CalculatorUser  Sep 26, 2019
 #7
avatar+1342 
0

I am going to have to make sure on the distances and all, but I can always jsut switch out the values since you have gave me the equations! Thank you.

 

I am curious as to why you included the part in bold

 

275,016 hrs * (55,345 * 1000)m  =  15,220,760,520,000 m

 

And the distance from the Earth to the Sun (on average) is ≈  149,668,992,000 m

 

So.....on Jan 2,2009......Voyager 2 was about   15,370,429,512,000 m from the Sun

 

Do i subtract the dsitance from earth to sun on average by the 15,220,760,520,000 m to get the final answer that is underlined?

jjennylove  Sep 26, 2019
 #8
avatar+104712 
+1

No.....the first distance given  (  15,220,760,520,000 m )  =  the distance Voyager 2 was from the Earth as of 1/2/2009

 

We must add the distance from the Sun to the Earth ( 149,668,992,000 m)  to get the final distance that Voyager 2 was from the Sun as of this date = 15,370,429,512,000 m

 

 

 

 

cool cool cool

 Sep 26, 2019
edited by CPhill  Sep 26, 2019
 #9
avatar+1342 
+1

When I first solved it by adding i got a different value so I was confused, but now resolving it I did get the same value. I just wanted to make sure! Thanks(:

jjennylove  Sep 26, 2019

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