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Suppose 73% of people like carrots.In a sample of 6 people ,What is the probability that at least 5 of them like carrots?

 Oct 9, 2015

Best Answer 

 #2
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This problem is an example of a binomial distribution. here n=6,p=0.73P[k of 6 like carrots]=(nk)pk(1p)nkThe probability that at least 5 like carrots is P[5]+P[6]=(65)(0.73)5(0.27)1+(66)(0.73)6(0.27)0=(6)(0.2073)(0.27)+(1)(0.1513)(1)=0.487126

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 Oct 9, 2015
 #1
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 Oct 9, 2015
edited by Guest  Oct 9, 2015
edited by Guest  Oct 9, 2015
 #2
avatar+6251 
+10
Best Answer

This problem is an example of a binomial distribution. here n=6,p=0.73P[k of 6 like carrots]=(nk)pk(1p)nkThe probability that at least 5 like carrots is P[5]+P[6]=(65)(0.73)5(0.27)1+(66)(0.73)6(0.27)0=(6)(0.2073)(0.27)+(1)(0.1513)(1)=0.487126

Rom Oct 9, 2015

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