+0  
 
+1
152
1
avatar+1050 

Suppose a does not equal 0. Compute log_{2^a} 2^b in terms of a and b.

 

Thanks!

 

Edit: I solved it, it is b/a

AnonymousConfusedGuy  Dec 11, 2017
edited by Guest  Dec 11, 2017
Sort: 

1+0 Answers

 #1
avatar+86649 
+2

log 2^a  2^b

 

This says that

 

[2^a]^n  =  2^b     

 

2^(a*n)  =  2^b     equating exponents, we have

 

a * n  =  b      divide both sides  by

 

n  =   b / a

 

 

cool cool cool

CPhill  Dec 11, 2017

6 Online Users

New Privacy Policy (May 2018)
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  Privacy Policy