Suppose a does not equal 0. Compute log_{2^a} 2^b in terms of a and b.
Thanks!
Edit: I solved it, it is b/a
log 2^a 2^b
This says that
[2^a]^n = 2^b
2^(a*n) = 2^b equating exponents, we have
a * n = b divide both sides by
n = b / a
+1452 
