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Suppose a does not equal 0. Compute log_{2^a} 2^b in terms of a and b.

 

Thanks!

 

Edit: I solved it, it is b/a

AnonymousConfusedGuy  Dec 11, 2017
edited by Guest  Dec 11, 2017
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 #1
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log 2^a  2^b

 

This says that

 

[2^a]^n  =  2^b     

 

2^(a*n)  =  2^b     equating exponents, we have

 

a * n  =  b      divide both sides  by

 

n  =   b / a

 

 

cool cool cool

CPhill  Dec 11, 2017

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