Suppose a does not equal 0. Compute log_{2^a} 2^b in terms of a and b.




Edit: I solved it, it is b/a

 Dec 11, 2017
edited by Guest  Dec 11, 2017

log 2^a  2^b


This says that


[2^a]^n  =  2^b     


2^(a*n)  =  2^b     equating exponents, we have


a * n  =  b      divide both sides  by


n  =   b / a



cool cool cool

 Dec 11, 2017

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