+0

# Suppose a quadrilateral ABCD with an inscribed circle has perimeter 24 and AB=5 . What is the length of segment CD?

0
4
3

Suppose a quadrilateral  ABCD with an inscribed circle has perimeter 24 and AB=5 . What is the length of segment CD?

Aug 14, 2023

#1
+1

Let's consider the properties of a quadrilateral with an inscribed circle (an incircle). One of the key properties is that the opposite sides of the quadrilateral are tangents to the incircle, and these tangents are equal in length.

Given that the perimeter of the quadrilateral ABCD is 24 and AB = 5, we can label the other sides as follows: BC = x, CD = y, and DA = z.

So, we have:

AB + BC + CD + DA = 24

Substituting the given values:

5 + x + y + z = 24

Solving for z:

z = 24 - 5 - x - y z = 19 - x - y

Since opposite sides of an inscribed quadrilateral are equal in length, we know that AD = BC and CD = AB.

So, we have:

AD = BC = x CD = AB = 5

Now, we can rewrite the perimeter equation with these lengths:

x + 5 + x + y + 19 - x - y = 24

Simplify:

2x + 24 = 24

Subtract 24 from both sides:

2x = 0

Divide by 2:

x = 0

However, a side length cannot be zero, which means there might be an issue with the problem statement or the approach taken. Please double-check the values and conditions given in the problem to ensure accuracy. If there is additional information or clarification, I would be happy to help further.

Aug 14, 2023
#2
+1

By Pitot Theorem, \(AB+CD = AC+BD = 12\), so \(CD=7\).

Aug 14, 2023