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# Suppose \$f\$ is a polynomial such that \$f(0) = 47\$, \$f(1) = 32\$, \$f(2) = -13\$, and \$f(3)=16\$. What is the sum of the coefficients of \$f\$?

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Suppose \$f\$ is a polynomial such that \$f(0) = 47\$, \$f(1) = 32\$, \$f(2) = -13\$, and \$f(3)=16\$. What is the sum of the coefficients of \$f\$?

If you answer, thanks! I'm pretty stuck right now.

Guest Apr 22, 2017
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#1
+2

Because f(1) will always equal the sum of the coeficcients, the answer is 32. This was a cool question, and I see how you could have gotten stuck.

Guest Apr 22, 2017
#2
+1509
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Whats with all the dollar signs?

MysticalJaycat  Apr 22, 2017
#3
+83974
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Very nice, MJ!!!!

CPhill  Apr 22, 2017
#4
+1509
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Thanks Cphill

MysticalJaycat  Apr 22, 2017

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