Suppose P, Q, and R are points in the plane such that PQ=1.8,PR=8.2, and angle PQR=\(90^\circ\). What is the perimeter of triangle PQR, and area.
Using the Pythagorean theorem...
1.8^2 (That is PQ) + (QR)^2 = 8.2^2 (That is PR)
Subtract 1.8^2 to both sides to get QR^2 = 8.2^2-1.8^2
QR^2 = 64
QR=8, and QR is the base. PQ is the height.
Get the triangle's area.
8*1.8*1/2=7.2
Is this correct???
