Suppose q is an angle in the standard position whose terminal side is in Quadrant II and tan Ø= - square root of 3

Suppose q is an angle in the standard position whose terminal side is in Quadrant II and tan Ø= - square root of 3

\(arctan( -\sqrt{3})=-60°\)

\(The \ free \ limb \ of \ the \ angle -60 ° \ forms \ the \ angle \ {\color{red}150 °} \ in \ the \ third \ quadrant.\)

.                                                                                           incorrect

  !

Thanks Alan! 

\(The \ free \ limb \ of \ the \ angle -60 ° \ forms \ {\color{blue}the \ angle \ 180° -60° = \ 120 °} \ in \ the \ third \ quadrant.\)

The angle is 120° to end up in quadrant II.  i.e. tan(120°) = -sqrt(3)

.