Suppose that a varies inversely with b^2. If a=9 when b=2, find the value of a when b=2 .

RektTheNoob Dec 18, 2017

#1**+3 **

Best Answer

What is the second value of b? Is it 2 or 3 ?? Look at the title and the body of the question !

At any rate, I believe it goes like this:

a = k x 1/b^2, where k = constant

9 = k x 1/2^2

k= 36

a = 36 x 1/4 =9 when b=2, or

a = 36 x 1/9 =4 when b=3

Guest Dec 18, 2017

edited by
Guest
Dec 18, 2017