Suppose that a varies inversely with b^2. If a=9 when b=2, find the value of a when b=2 .
What is the second value of b? Is it 2 or 3 ?? Look at the title and the body of the question !
At any rate, I believe it goes like this:
a = k x 1/b^2, where k = constant
9 = k x 1/2^2
a = 36 x 1/4 =9 when b=2, or
a = 36 x 1/9 =4 when b=3