Suppose that \(\Join\) is an operation defined by \(x \Join y = (x+2)(y-3)\). What is \(((t) \Join (t+2)) - ((t+1) \Join (t+1))\)?
+40 (Sorry I do not have a picture or key for that operation thingy you have but I'll try my best)
so if |><| means (x+2)(y-3) and we're trying to find ((t)|><|(t+2))-((t+1)|><|(t+1)), first we must expand it
((t)|><|(t+2)) would have t represent x and (t+2) represent y so (t+2)((t+2)-3). We can expand that to t^2+t-2
Next we have ((t+1)|><|(t+1)) We do the same thing (t+1+2)(t+1-3) which expands to t^2+t-6.
(t^2+t-2)-(t^2+t-6)=-8
Pretty sure that's correct
