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Suppose that there is a right triangle ABC such that the legs AB and AC have lengths 4sqrt2 and 2 respectively. What is the length of the median BM?

 Aug 1, 2017
 #1
avatar+129852 
+5

  

 

We can use the Pythagorean Theorem, here

 

BM  =  sqt [ (4sqrt(2) ^2 + 1^2 ]  =    sqrt ( 32 + 1 )  =   sqrt (33) ≈  5.74

 

Here's a pic :

 

 

 

cool cool cool

 Aug 1, 2017
 #2
avatar+118677 
+3

CPhill's answer is drawing criticism but it is CORRECT.

 

Thanks Chris :)

 Jul 26, 2019
 #3
avatar+1713 
+5

I use the same math thing as the user who posted this, and I came here to check my answer, and i put in sqrt33.

it was the wrong answer

I thought it was sqrt(32+1)

just like CPhill...

 Jul 29, 2019

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