+270 So, im a little stuck on what to do next.. im trying to find the surface area of a revolution about the x-axis for the following:
\(y=x^2, [0, 4]\)
The derivative of x^2 is 2x...
so plugging in my values into the formula, im getting:
\(s=2pi\int_{0}^{4}x^2\sqrt{1+(2x)^2}dx\)
i'm actually not sure what the next step is?
