surface area

This is your Fast Answer

What is the surface area of a square pyramid

for a base length of 2 and a slant length of 7?

lateral surface area = 28 m²
base surface area = 4 m²
total surface area = 32 m²

The area of the base  = (length of one side of the base)² = 2² = 4 square units

Also, there are 4 triangles, each with a base = 2 and a height = slant height =7

So each has an area = (1/2)(b)(h) = (1/2)(2)(7) = 7

And 4 tmes this = (4)(1/2)(2)(7) = (2)(2)(7)  = 28 sq units

So the "formula" for the surface area = b² + 2(b)(h), where b is one side of the base and h is the slant height of the pyramid

And the surface area of this particular pyramid = (28 + 4) sq units = 32 sq units.