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Suppose a, b, c, and d are real numbers which satisfy the system of equations

a + 2b + 3c + 4d = 10

4a + b + 2c + 3d = 4

3a + 4b + c + 2d = -10

2a + 3b + 4c + d = −4.

Find a + b + c + d.

 Feb 13, 2022
 #1
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Hint:   Add all of the equations together....then divide by 10....

 Feb 13, 2022
 #2
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I think this question has already been posted on this website. 

 

Anyways, just like EP said, adding them should get your answer laugh

 Feb 14, 2022

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