Suppose a, b, c, and d are real numbers which satisfy the system of equations
a + 2b + 3c + 4d = 10
4a + b + 2c + 3d = 4
3a + 4b + c + 2d = -10
2a + 3b + 4c + d = −4.
Find a + b + c + d.
Hint: Add all of the equations together....then divide by 10....
I think this question has already been posted on this website.
Anyways, just like EP said, adding them should get your answer