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Suppose a, b, c, and d are real numbers which satisfy the system of equations

a + 2b + 3c + 4d = 10

4a + b + 2c + 3d = 4

3a + 4b + c + 2d = 10

2a + 3b + 4c + d = 4.

Find a + b + c + d.

 Feb 3, 2022
 #1
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Add all the equations: 

 

\(10a+10b+10c+10d=28\)

 

Divide by 10

 

\(a + b+c+d=\color{brown}\boxed{2.8}\)

 Feb 3, 2022

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