For what negative value of k is there exactly one solution to the system of equations y = 2x^2 + kx + 6, y = -x - 8?
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That way, people can learn and share ideas.
y = 2x^2 + kx + 6
y = -x - 8
-x - 8 = 2x^2 + kx + 6
0 = 2x^2 + (k+1)x + 14
There is one solution when the discriminant is 0.
(k+1)^2 - 4(2)(14) = 0
(k+1)^2 = 112
k+1 = +/- 4sqrt(7)
k = -1 +/- 4sqrt(7)
I did not seem to get 16.
=^._.^=
k has to be negative, so the answer is \(\color{brown}\boxed{1 - 4 \sqrt7}\)
Here is the graph: https://www.desmos.com/calculator/fwa8nyw6it