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One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)

 Feb 20, 2024
 #1
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\(ab^4=48\)\(ab^2=4\)

\(ab^4=(ab^2)b^2=4b^2=48\)

\(b^2=12\)\(b=\pm2\sqrt{3}\)

If b has to be positive as specified possibly in your question, then type 2sqrt(3), if not, then type -2sqrt(3).

 Feb 20, 2024

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