One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
\(ab^4=48\), \(ab^2=4\)
\(ab^4=(ab^2)b^2=4b^2=48\)
\(b^2=12\), \(b=\pm2\sqrt{3}\)
If b has to be positive as specified possibly in your question, then type 2sqrt(3), if not, then type -2sqrt(3).
+400 
