For what negative value of k is there exactly one solution to the system of equations y = 2x^2 + kx + 6, y = -x - 8?
Hint: Substitute $y=-x-8$ and put into the equation so you get a quadratic. In a quadratic equation, the equation has only one solution if the discriminant is $0$. In $ax^2+bx+c$, the discriminant is $b^2-4ac$. From here you should be able to solve for k. Good luck!