For a certain value of k, the system
3a + 4b = 7
3a + 2b = k - 2b
has infinitely many solutions What is k?
+36916 re-write the second equation to
3a + 4b = k now, if the two equations are equal, there are infinite solutions.... so k = 7
+36916 re-write the second equation to
3a + 4b = k now, if the two equations are equal, there are infinite solutions.... so k = 7
