find the value of k for which the system of equations has a unique solution 2x+ky-9=0 , kx+3y-13=0.
find the value of k for which the system of equations has a unique solution 2x+ky-9=0 , kx+3y-13=0.
Hello Guest!
2x+ky-9=0 , kx+3y-13=0
\(y=(-2x+9)/k\\ y=(-kx+13)/3\)
The system of equations has unique solutions for many values of k.
\(k\in \{\) \(-1,\) \(4,\) \(5,\) \(etc.\ \}\)
\(x\in \{\) \(\ 8,\) \(2.5,\) \(2\}\)
\(y\in \{\) \(\ 7,\) \(1,\) \(1\}\)
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