systems

WAIT A SECOND! Let's note something real quick. 

First, let's look at the first equation. We want only two equations, we isolate p in terms of r. 

We get that

\(p=3+2q\)

Subsituting this value of p into the second and third equation, we get the system with r and q, we get

\(q-2r=-2+q\\ 3+2q+r=9+3+2q\)

Now, focusing on the first equation of the new system, isolating r, we find that

\(r=1\)

Plugging in this value for r into the second equation, we have that

\(3+2q+1=2q+12\\2q+4=2q+12\\-8=0\)

THIS IS DEFINITELY NOT TRUE. 

In conclusion, we know that this system has NO SOLUTIONS. 

I think this is right...

Thanks! :)