The table of values represents a polynomial function f (x).
How much greater is the average rate of change over the interval [5, 7] than the interval [2, 4]?
X values: 2 3 4 5 6 7
F(x) values: 39 125 287 549 935 1469
Thanks for all of your help
+9481 avg rate of change over the interval [5, 7] = \(\frac{f(7)-f(5)}{7-5}\)
avg rate of change over the interval [5, 7] = \(\frac{1469-549}{7-5}\)
avg rate of change over the interval [5, 7] = \(\frac{920}{2}\)
avg rate of change over the interval [5, 7] = 460
avg rate of change over the interval [2, 4] = \(\frac{f(4)-f(2)}{4-2}\)
avg rate of change over the interval [2, 4] = \(\frac{287-39}{4-2}\)
avg rate of change over the interval [2, 4] = \(\frac{248}{2}\)
avg rate of change over the interval [2, 4] = 124
How much greater is the avg rate of change over the interval [5, 7] than the avg rate of change over the interval [2, 4] ? That is...how much greater is 460 than 124 ?
460 - 124 = 336
460 is 336 greater than 124 .
+9481 avg rate of change over the interval [5, 7] = \(\frac{f(7)-f(5)}{7-5}\)
avg rate of change over the interval [5, 7] = \(\frac{1469-549}{7-5}\)
avg rate of change over the interval [5, 7] = \(\frac{920}{2}\)
avg rate of change over the interval [5, 7] = 460
avg rate of change over the interval [2, 4] = \(\frac{f(4)-f(2)}{4-2}\)
avg rate of change over the interval [2, 4] = \(\frac{287-39}{4-2}\)
avg rate of change over the interval [2, 4] = \(\frac{248}{2}\)
avg rate of change over the interval [2, 4] = 124
How much greater is the avg rate of change over the interval [5, 7] than the avg rate of change over the interval [2, 4] ? That is...how much greater is 460 than 124 ?
460 - 124 = 336
460 is 336 greater than 124 .
