+0  
 
0
7
1
avatar+0 

A circular table is pushed into a corner of the room, where two walls meet at a right angle.  A point $P$ on the edge of the table (as shown below) has a distance of $10$ from one wall, and a distance of $13$ from the other wall.  Find the radius of the table.

 

 Feb 14, 2024
 #1
avatar+128732 
+1

(r-10)^2 + (r -13)^2  = r^2

 

r^2 - 20r + 100 + r^2 -26r + 169  = r^2

 

r^2 - 46r + 269  =  0

 

r = 23 + 2sqrt (65)  ≈  39.125

 

cool cool cool

 Feb 14, 2024

0 Online Users