In triangle ABC, AB=5, AC=6, and BC=8. Circles are drawn with centers A, B, and C, so that any two circles are externally tangent. Find the sum of the areas of the circles.
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In triangle ABC, AB=5, AC=6, and BC=8. Circles are drawn with centers A, B, and C so that any two circles are externally tangent. Find the sum of the areas of the circles.
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AB = 1.5 + 3.5 = 5 AC = 1.5 + 4.5 = 6 BC = 3.5 + 4.5 = 8
Area = (1.52pi) + (3.52pi) + (4.52pi) ==> A = 34 3/4pi
