Please Help with the following question.... It is a practice problem that I would like to solve:
Find the equation of a line tangent to the circle (x+1)^2+(y-4)^2=25 at the point (3, 1)
Appreciate you guys
+130081 The center of the circle is ( -1, 4 )
And the given point is ( 3, 1 )
Finding the slope between these two points, we have
[ 4 - 1 ] / [ -1 - 3] = [ 3] / [-4] = -3/4
And the slope of the tangent ine will be the negative reciprocal of this = 4/3
So.....the equation of the tangent line is :
y = (4/3) (x - 3) + 1 simplify
y = (4/3)x - 4 + 1
y = (4/3)x - 3
Here's the graph : https://www.desmos.com/calculator/5u5jc97jd5
