+592 \((x - 1 + 2)^2 = (2x - 4)^2 + (x - 1)^2\)
\(x^2 + 2x + 1 = 4x^2 - 16x + 16 + x^2 - 2x + 1\)
\(2x = 4x^2 - 18x + 16\)
\(x = 2x^2 - 9x + 8\)
\(2x^2 - 10x + 8 = 0\)
\(2(x^2 - 5x + 4) = 0\)
2(x - 1)(x - 4) = 0
(x - 1)(x - 4) = 0
x = 4
x = 1
However, side WU is (x - 1) so x can't be 1 since the side will be 0, which is impossible.
Which means your answer is 4
