Tell whether the ordered pair is a solution of the linear system.

Input -4 for x and 2 for y into each part of the system, and solve them to see if they fit. For example:

5(-4)-2(2)=14

5*-4=-20 and 2*2=4

-20-4=14

-20+(-4)=-24

-24 does not equal 14. So the ordered pair is not a solution to the linear system.

Here's the second equation of the system:

3(-4)+4(2)=11

3*-4=-12 and 4*2=8

-12+8=11

-12+8=-4

-4 does not equal 11, so the ordered pair is not a solution of the second equation of the linear system either.

An ordered pair needs to solve both the equations of the system to be a solution to the system.

Solve the following system:
{5 x-2 y = 14 |     (equation 1)
3 x+4 y = 11 |     (equation 2)
Subtract 3/5 × (equation 1) from equation 2:
{5 x-2 y = 14 |     (equation 1)
0 x+(26 y)/5 = 13/5 |     (equation 2)
Multiply equation 2 by 5/13:
{5 x-2 y = 14 |     (equation 1)
0 x+2 y = 1 |     (equation 2)
Divide equation 2 by 2:
{5 x-2 y = 14 |     (equation 1)
0 x+y = 1/2 |     (equation 2)
Add 2 × (equation 2) to equation 1:
{5 x+0 y = 15 |     (equation 1)
0 x+y = 1/2 |     (equation 2)
Divide equation 1 by 5:
{x+0 y = 3 |     (equation 1)
0 x+y = 1/2 |     (equation 2)
Collect results:
Answer: | x = 3               y = 1/2