What is the smallest positive integer \(\frac{n}{n+101}\) such that is equal to a terminating decimal?
Thanks!
In order for a fraction to have a terminating decimal representation the denominator must
have factors of only powers of 2 or 5.
when n=24, n+101=125 which is 53
This appears to be the smallest positive integer meeting the criterion.
Thanks rom :)
+152 
