Terms with exponents

hi Juriemagic  

This is an unusual question :)

$5*3^x-9*3^{x-2} \over 3^x-3^{x-1}\\ =(5*3^x-9*\frac{3^x}{9})\div(3^x-\frac{3^x}{3})\\ =(5*3^x-3^x)\div(\frac{3*3^x-3^x}{3})\\ =(4*3^x)\div(\frac{2*3^x}{3})\\ =(4*3^x)\times(\frac{3}{2*3^x})\\ =(4)\times(\frac{3}{2})\\ =6$

Note, junemagic

5 * 3^x  -  3^x  = 

5 * 3^x   -   1 * 3^x = 

3^x  ( 5 - 1) =

3^x * 4  =

4 * 3^x