Thanks Melody for helping me so much on my last question! Another question!!

The form of a quadratic is   f(x) = ax^2 + bx + c .......and we have that

24 = a(1)^2  + b(1)  + c    →      24   =  a + b + c         (1)

0 =   a(4)^2  + b(4) + c    →         0  = 16a + 4b + c     (2)

60 = a(7)^2 + b(7) + c   →         60  =  49a +  7b + c    (3)

Multiply  (1) by -1 and add it to  (2)    

-24  = 15a + 3b      (4)

Multiply (1) by -1 and add it to (3)

36 =  48a + 6b   (5)

Multiply   (4) by -2 and add to (5)

84   = 18a    divide both sides by 18

84/18 = 14/3   = a

Substituting this into (4)  to find b, we have

-24  = 15(14/3)  + 3b

-72  = 15*14 + 9b

-72  = 210 + 9b

-282  = 9b     divide both sided by 9

-282/9   = -94/3  = b

And using (1)  to find  "c"  

14/3 -  94/3 + c   = 24

-80/3  + c = 24

c = 72/3 + 80/3 =   152/3

So....the quadratic is

y f(x) = (14/3)x^2 - (94/3)x + 152/3

And f(-1)   =    14/3  + 94/3 + 152/3   =   260/3   

Here's a graph : https://www.desmos.com/calculator/jjflwmz37w

Here's the graph :