+678 Hello, I have a puzzle for you that you are welcome to solve. (This is not mine puzzle!)
There are rules:
Make each equation true using common mathematical operations.
1. You cannot introduce any new digits (for example, \(\sqrt[3]{}\) is not allowed).
2. You must have the result be equal to 6 (you cannot use the \(\not=\) symbol).
Thanks to Tyler Cenko!
Thanks to Caio Cerqueira, from Brazil!
The solution is by a YouTube video, namely:
https://www.youtube.com/watch?v=h2vkrxvh76c
\(0\) \(0\) \(0\) \(=6\)
\(1\) \(1\) \(1\) \(=6\)
\(2\) \(2\) \(2\) \(=6\)
\(3\) \(3\) \(3\) \(=6\)
\(4\) \(4\) \(4\) \(=6\)
\(5\) \(5\) \(5\) \(=6\)
\(6\) \(6\) \(6\) \(=6\)
\(7\) \(7\) \(7\) \(=6\)
\(8\) \(8\) \(8\) \(=6\)
\(9\) \(9\) \(9\) \(=6\)
\(10\) \(10\) \(10\) \(=6\)
Try it to solve!
In the video there are only some solutions and not all,
type in the calculator an arithmetical task, if you aren't sure!
Thanks to all who try to solve the challenge.
Straight
+118687
I got all of them, without cheating.
Can I have a cookie now?
Added after:
I just looked at the answers in the video.
two of them are better than mine.
I used the floor function for 2 of them (which noone said was against the rules) but they can all be done without using floor or ceiling functions.
+678 I can't use emojis, but you still get a cookie! :)
In the video they used faculty \(!\), it applies:
\(0!=1\)
Straight
+2511 For sure, Presh Talwalkar is a skilled mathematician and articulate teacher of the subject, but the arbitrary pile of BS in the introduction means he was asleep at the calculator when he made this video.
The first thing that came to mind while watching the video is why is the square root allowed? If the cube root is not allowed because it introduces a three (3) the square root should not be allowed because it introduces a two (2). “...You cannot introduce any new digits, so the cube root is not allowed because it involves the digit (3).” (In any case, the last time I checked, the cube root function is not a digit, so the reason is a complete non sequitur.)
I noted a comment posted thirty months after the introduction of the video making this point. The 479 responses both agree and disagree that the square root introduces a (2).
I might assume the arbitrary allowance for square roots in solving four of these problems comes from Brazilian math theory, which isn’t always consistent. Dragonlance hilariously points this out:
GA
+2511 The above is not a long text. It may seem that way to you because you are still learning how to read and write Standard English. You have a long way to go... Your communication skills are so poor and chaotic that is seems intentional. They are much more worser than your math skills.
Understanding what you write often requires a large amount of effort. None of the AI assisted babble translators offer much help. I am marginally successful (or not) to a point because I have extensive, practiced skills in translating the dialects of moron, imbecile, and idiot. Even so, it is still a time consuming chore. If you could consistently maintain at least a minimum moron-level of communication, it would be easier... Not easy, just easier.
Keep in mind that verbose is NOT the same as articulate. Using made-up “English” words, whether you make them up yourself or they were taught to you, require several uses in various contexts before they can be translated consistently. “Onliest” is one you’ve used in a post. If you use this a few more times, I should be able to translate this word in context.
Here, you might be able to understand this more better:
It is not for me to demand English properly from writing by you. But I sugest now understanding without this is not completely possible without most all the possibilities examined. So if you can give rise to more better possibilities, then my not demanding English properly from writing by you at the moment will require less demanding reporting when moments like this are in the future maybe. I’m not writing the new rules; I’m just explaining the rules that will help stand your writing more better comprehensible. Or, ![[not]](/img/emoticons/smiley-undecided.gif "[not]")
GA
