The age of a man 3 years ago was 11 times the age of his son. The ratio of their ages after 15 years will be 2:1
The age of a man 3 years ago was 11 times the age of his son. The ratio of their ages after 15 years will be 2:1
And I assume you want to find their current ages??
Let x and y be the son's and father's ages, now...so we have
11(x-3) = y-3 → 11x - 33 = y - 3 → 11x - 30 = y (1)
2(x + 15) = y + 15 → 2x + 30 = y + 15 → 2x + 15 = y
And setting the "y's" equal, we have
11x - 30 = 2x + 15 rearrange
9x = 45 solve for x
x = 5, and that's the son's age now
And using (1)
11(5) - 30 = y = 25 and that's the father's age now
The age of a man 3 years ago was 11 times the age of his son. The ratio of their ages after 15 years will be 2:1
\small{\text{ s = son and m = man }$\\\\$ \begin{array}{lrcllrcl} (1) & (m-3) &=& 11*(s-3) & | \quad (m-3) &=& 11s-33\\ (2) & \frac{m+15}{s+15} &=& \frac{2}{1} & | \quad m+15 &=& 2s+30\\ \hline (2)-(1):& 18 &=& -9s+63 & | :9\\ &2 &=& -s+7\\ & s&=&5 \\ \hline (1): & m-3 &=& 55-33\\ & m &=& 3+22\\ & m &=& 25 \\ \hline \end{array}
The age of the man is 25 and the age of his son is 5.
The age of a man 3 years ago was 11 times the age of his son. The ratio of their ages after 15 years will be 2:1
And I assume you want to find their current ages??
Let x and y be the son's and father's ages, now...so we have
11(x-3) = y-3 → 11x - 33 = y - 3 → 11x - 30 = y (1)
2(x + 15) = y + 15 → 2x + 30 = y + 15 → 2x + 15 = y
And setting the "y's" equal, we have
11x - 30 = 2x + 15 rearrange
9x = 45 solve for x
x = 5, and that's the son's age now
And using (1)
11(5) - 30 = y = 25 and that's the father's age now