The age of a man 3 years ago was 11 times the age of his son. The ratio of their ages after 15 years will be 2:1
The age of a man 3 years ago was 11 times the age of his son. The ratio of their ages after 15 years will be 2:1
And I assume you want to find their current ages??
Let x and y be the son's and father's ages, now...so we have
11(x-3) = y-3 → 11x - 33 = y - 3 → 11x - 30 = y (1)
2(x + 15) = y + 15 → 2x + 30 = y + 15 → 2x + 15 = y
And setting the "y's" equal, we have
11x - 30 = 2x + 15 rearrange
9x = 45 solve for x
x = 5, and that's the son's age now
And using (1)
11(5) - 30 = y = 25 and that's the father's age now
The age of a man 3 years ago was 11 times the age of his son. The ratio of their ages after 15 years will be 2:1
$$\small{\text{ s = son and m = man }$\\\\$
\begin{array}{lrcllrcl}
(1) & (m-3) &=& 11*(s-3) & | \quad (m-3) &=& 11s-33\\
(2) & \frac{m+15}{s+15} &=& \frac{2}{1} & | \quad m+15 &=& 2s+30\\
\hline
(2)-(1):& 18 &=& -9s+63 & | :9\\
&2 &=& -s+7\\
& s&=&5 \\
\hline
(1): & m-3 &=& 55-33\\
& m &=& 3+22\\
& m &=& 25 \\
\hline
\end{array}$$
The age of the man is 25 and the age of his son is 5.
The age of a man 3 years ago was 11 times the age of his son. The ratio of their ages after 15 years will be 2:1
And I assume you want to find their current ages??
Let x and y be the son's and father's ages, now...so we have
11(x-3) = y-3 → 11x - 33 = y - 3 → 11x - 30 = y (1)
2(x + 15) = y + 15 → 2x + 30 = y + 15 → 2x + 15 = y
And setting the "y's" equal, we have
11x - 30 = 2x + 15 rearrange
9x = 45 solve for x
x = 5, and that's the son's age now
And using (1)
11(5) - 30 = y = 25 and that's the father's age now