if the price of a pencil is 36% lower than the price of a pen,then the price of a pen is ?

1.)36%higher than a pencil

2.)43.75 higher than a pencil

3.)56.25 % higher than a pencil

4.)64% higher than a pencil

Guest Feb 17, 2015

#1**+10 **

If the price of a pencil is 36% lower than the price of a pen, then the pencil's price is 1- 36% of the pen's price =.64pen

For argument's sake, let the pen's price be 1 .....Then the pencil's price = .64

Then

.64( 1 + P) = 1 where P is the % we're looking for...divide both sides by .64

1 + P = 1/.64

1 + P = 1.5625 subtract 1 from both sides

P = .5625 = 56.25%

Then the pen is 56.25% more than the pencil.

Another way to see this is that .36 must be added to the pencil's price of .64 to get the pen's price.

Thus 36/64 = 56.25% of the pencil's price must be added.......

.

CPhill
Feb 17, 2015

#1**+10 **

Best Answer

If the price of a pencil is 36% lower than the price of a pen, then the pencil's price is 1- 36% of the pen's price =.64pen

For argument's sake, let the pen's price be 1 .....Then the pencil's price = .64

Then

.64( 1 + P) = 1 where P is the % we're looking for...divide both sides by .64

1 + P = 1/.64

1 + P = 1.5625 subtract 1 from both sides

P = .5625 = 56.25%

Then the pen is 56.25% more than the pencil.

Another way to see this is that .36 must be added to the pencil's price of .64 to get the pen's price.

Thus 36/64 = 56.25% of the pencil's price must be added.......

.

CPhill
Feb 17, 2015

#2**+5 **

Thanks Chris this is a good question. I am just going to think about it myself for a bit.

My pencil is a lead pencil so L for the pencil

and my pen is Blue so B for the pen

$$\\64\%\; of\; B=L\\

0.64B=L\\

$divide both sides by 0.64$\\

B=\frac{L}{0.64}=\frac{1}{0.64}\times L = 1.5625L$$

So the blue pen is 156.25% the cost of the lead pencil

In other words the blue pen is 56.25% more expensive than the lead pencil.

Melody
Feb 17, 2015