the average of 4 consecutive even integers is 17. Is there a solution, and if there is what are the integers and what is the process for solving this problem?
+817 14,16,18,and 20. These even numbers are conescutive and average to 17. All you have to do is look at the closest 2 numbers higher and 2 numbers lower than 17!
+129933 Let 2N be the first even number
2N + 2 the next
2N + 4 the next
2N + 6 the last .......so we have
Average = [sum of the numbers ] / [ how many numbers we have]
17 = [ 2N + ( 2N + 2) + ( 2N + 4) + (2N + 6)] / 4 simplify
17 = [ 8N + 12] / 4 multiply both sides by 4
68 = 8N + 12 subtract 12 from both sides
56 = 8N divide both sides by 8
7 = N
So the first even number = 2(N) = 2(7) = 14
Which means that the next three are 16, 18 and 20
the average of 4 consecutive even integers is 17. what are the integers and what is the process for solving this problem?
n +(n+2) + (n+4) + (n+6)=17 x 4
4n+ 12 = 68 subtract 12 from both sides
4n=56 divide both sides by 4
n=56/4
n=14. So the numbers are:14, 16, 18, 20
