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The center of a circle is located at (6, −1) . The radius of the circle is 4.

 

What is the equation of the circle in general form?

A.)    x2+y2−12x+2y+21=0

B.)    x2+y2+12x−2y+33=0

C.)    x2+y2+12x−2y+21=0

D.)    x2+y2−12x+2y+33=0

Gwendolynkristine  May 5, 2017
 #1
avatar+87301 
+2

 

First write in center-radius form

 

( x - 6)^2 + ( y + 1)^2  = 16       expand

 

x^2 - 12x + 36 + y^2 + 2y + 1  =  16       simplify

 

x^2 + y^2 - 12x + 2y + 21  =  0  ......  "A"  is correct

 

 

cool cool cool

CPhill  May 5, 2017

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