+0  
 
+1
360
1
avatar+163 

The center of a circle is located at (6, −1) . The radius of the circle is 4.

 

What is the equation of the circle in general form?

A.)    x2+y2−12x+2y+21=0

B.)    x2+y2+12x−2y+33=0

C.)    x2+y2+12x−2y+21=0

D.)    x2+y2−12x+2y+33=0

Gwendolynkristine  May 5, 2017
Sort: 

1+0 Answers

 #1
avatar+79835 
+2

 

First write in center-radius form

 

( x - 6)^2 + ( y + 1)^2  = 16       expand

 

x^2 - 12x + 36 + y^2 + 2y + 1  =  16       simplify

 

x^2 + y^2 - 12x + 2y + 21  =  0  ......  "A"  is correct

 

 

cool cool cool

CPhill  May 5, 2017

15 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details