The coordinates of the endpoints of QS are Q(−9,8) and S(9,−4). I'm confused about finding the numerator and the denominator of the ratio.
Hi. It seems like you already know the coordinates of R. If you do, assume A:B, it's also a/b.
Hey, GM!!!
Note that if QR :RS = 1 : 2....then (think about this)....QR must just be 1 / [ 1 + 2 ] = 1/3 of the total length of QS
So numerator = 1
And denominator = 3
Here's the way to find R
( -9 + (1/3) (9 - - 9) , 8 + (1/3) ( -4 - 8) ) =
(-9 + (1/3)(18) , 8 + (1/3) (-12) ) =
( -9 + 6, 8 - 4) =
(-3, 4) = R
See this image to verify this :
Thanks CPhill! This makes more sense now. I thought I had to plug in the coordinates and solve them somehow.