The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is measured in meters.
Find an expression for the instantaneous velocity v(t) of the particle at any given point in time.
Question 13 options:
6t3 – 5
5t3 + 6
6t2 + 5
5t2 – 6
The derivative of the position function gives the velocity function
2 t^3 + 5 t -2 derivative = 6 t^2 + 5