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The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is measured in meters.

 

Find an expression for the instantaneous velocity v(t) of the particle at any given point in time.
 

Question 13 options:

6t3 – 5

5t3 + 6

6t2 + 5

5t2 – 6

 Jun 9, 2020
 #1
avatar+26620 
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The derivative of the position function gives the velocity function

 

2 t^3 + 5 t -2    derivative   =   6 t^2 + 5

 Jun 9, 2020
 #2
avatar+39 
0

thanks!

 Jun 9, 2020

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