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The Easton High School marching band has 52 members and the Weston High School marching band has 65 members. They are going to march in a parade. How can they be arranged so that each row has the same number of players? The players from each school have to be separate.

rows of 13

rows of 5

rows of 4

rows of 8

 Jun 25, 2014

Best Answer 

 #1
avatar+3454 
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Basically what we need to figure out is what the common factors are between 52 and 65.

How I know we have to do this is because the two schools have to have the same number of people in their rows, but their rows have to be sepparate (in other words, you can't add the total members together then organize them into rows)

So, let's use the "factor tree" to find the factors of these numbers:

Aha! We have found a common factor (a factor both of these numbers have) of 13!

So, the players should be aranged in rows of 13 to have even numbers of players in a row.

 Jun 26, 2014
 #1
avatar+3454 
+5
Best Answer

Basically what we need to figure out is what the common factors are between 52 and 65.

How I know we have to do this is because the two schools have to have the same number of people in their rows, but their rows have to be sepparate (in other words, you can't add the total members together then organize them into rows)

So, let's use the "factor tree" to find the factors of these numbers:

Aha! We have found a common factor (a factor both of these numbers have) of 13!

So, the players should be aranged in rows of 13 to have even numbers of players in a row.

NinjaDevo Jun 26, 2014

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