The ellipse x^2/49+y^2/b^2=1 has foci at (5,0) and (-5,0).
(a) Fimd the length of a semi major axis of this ellipse
(b)compute the value of b
For A i got 7 by doing sqrt 48 but B im a bit confused. I did sqrt(a^2-c^2)=sqrt(7^2-5^2)=sqrt24=2sqrt6. So would the value of be just 2sqrt6 or do I need to do some other step?