+0  
 
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avatar+108 

The ellipse x^2/49+y^2/b^2=1 has foci at (5,0) and (-5,0).

(a) Fimd the length of a semi major axis of this ellipse

(b)compute the value of b

 Feb 18, 2021
 #1
avatar+108 
+2

For A i got 7 by doing sqrt 48 but B im a bit confused. I did sqrt(a^2-c^2)=sqrt(7^2-5^2)=sqrt24=2sqrt6. So would the value of be just 2sqrt6 or do I need to do some other step?

 Feb 18, 2021
 #2
avatar+116126 
+2

x^2/49  + y^2/b^2  = 1

 

a  = 7       =   length of semi-major  axis

c  = 5

 

b =   sqrt   (7^2  - 5^2)   = sqrt (24)  =   2sqrt (6)

 

Good job , WDIPT    !!!!

 

 

cool cool cool

 Feb 18, 2021

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