The endpoints of a diameter of a circle are (6,2) and (−2,5) .
What is the standard form of the equation of this circle?
Find the diameter sqrt (x1-x2)^2 + (y1-y2)^2 ) 1/2 of this is r the radius
Find the MIDPOINT ....this will be the center (h,k)
from 6 to -2 is 8 units midpoint will be 4 units from either end at 2
from 2 to 5 is 3 units midpoint will be 1 1/2 from either end at 3 1/2 so (h.k) = (2, 3 1/2)
Standard form of a circle is
(x-h)^2 + (y-k)^2 = r^2 You now have all of the building parts....put it together and done.
Hi, can you please set up the diameter equation for me so I can solve it because I think I keep doing it wrong somehow