The equation \(y=-16t^2+22t+45\) describes the height (in feet) of a ball thrown upwards at 22 feet per second from 44 feet above the ground. Find the time (in seconds) when the ball will hit the ground. Express your answer as a common fraction.
When y is 0 is when the ball hits the ground. We can treat this as a quadratic equation which will be
Since the answer can result in negative seconds, the answers is 5/2 seconds.