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The equation \(y=-16t^2+22t+45\) describes the height (in feet) of a ball thrown upwards at 22 feet per second from 44 feet above the ground. Find the time (in seconds) when the ball will hit the ground. Express your answer as a common fraction.

 Dec 2, 2020
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When y is 0 is when the ball hits the ground. We can treat this as a quadratic equation which will be

-16t^2+22t+45=0

factors into

(8t+9)(2t-5)=0

t=-9/8, 5/2

Since the answer can result in negative seconds, the answers is 5/2 seconds.

 Dec 2, 2020

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