The equation \(y=-16t^2+22t+45\) describes the height (in feet) of a ball thrown upwards at 22 feet per second from 44 feet above the ground. Find the time (in seconds) when the ball will hit the ground. Express your answer as a common fraction.
+40 When y is 0 is when the ball hits the ground. We can treat this as a quadratic equation which will be
-16t^2+22t+45=0
factors into
(8t+9)(2t-5)=0
t=-9/8, 5/2
Since the answer can result in negative seconds, the answers is 5/2 seconds.
