+0  
 
0
261
3
avatar+504 

The point A has the coodinates (2 , 5)

The point B has the coodinates (6 , 7)

 

The equation of AB is y = 1/2x + 4 

Find the equation of the perpendicular bisector to AB

YEEEEEET  Feb 25, 2018
 #1
avatar+92895 
+1

We need to find the mid-point of AB....this is :

 

[  (2 + 6)/2, (5 + 7) /2)  =   ( 8 / 2, 12 / 2)   = (4, 6)   

 

The perpendicular bisector will go through this point...and it will have a slope of -2

 

So .....its equation is

 

y  =  -2 ( x - 4)   + 6  

 

y = -2x + 8 + 6

 

y = -2x + 14

 

 

cool cool cool

CPhill  Feb 25, 2018
 #2
avatar+504 
0

Can you explain where the x-4 came from please

YEEEEEET  Feb 25, 2018
 #3
avatar+92895 
+1

The equation is

 

y  = m(x - h)  + k

 

Where m is the slope of the perpendicular bisector.....and ( h, k)  = ( 4, 6)  which is a point on the perpedicular bisector....in this case, it's the midpoint of AB

 

 

cool cool cool

CPhill  Feb 25, 2018

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