+1995 The equation y=58−x represents the temperature, y, in degrees Fahrenheit and the time, x, in hours from 6 p.m. to 9 a.m. on a certain day.
Let x = 0 represent the temperature at 6 p.m.
What is the average rate of change in temperature from 6 p.m. to 9 a.m.?
2°F per hour
−1°F per hour
−2°F per hour
1°F per hour
+37146 Temp at 9 AM (15 hours form 6 PM) y = 58 - 15 = 43 degrees
Temp at 6 PM = y = 58-(0) = 58
(58-43) /( 6pm-9am) =
15/(0-15) = - 1 degree per hour (negative because the temperature is DROPPING from 6PM to 9 AM)
+1995 Oh okay that makes more sense with your explanation , I was thinking it was just postitive 1 but I do see my mistake. Thank you
