+0  
 
0
40
2
avatar+393 

The equation y=58−x represents the temperature, y, in degrees Fahrenheit and the time, x, in hours from 6 p.m. to 9 a.m. on a certain day.

Let x = 0 represent the temperature at 6 p.m.

What is the average rate of change in temperature from 6 p.m. to 9 a.m.?

 

2°F per hour

 

−1°F per hour

 

−2°F per hour

 

1°F per hour

 Jan 8, 2019
 #1
avatar+15350 
+3

Temp at 9 AM   (15 hours form 6 PM)      y = 58 - 15 = 43 degrees

Temp at 6 PM     = y = 58-(0) = 58

 

(58-43) /( 6pm-9am) =

15/(0-15)    =  - 1 degree per hour     (negative because the temperature is DROPPING from 6PM to 9 AM)

 Jan 8, 2019
edited by ElectricPavlov  Jan 8, 2019
 #2
avatar+393 
+1

Oh okay that makes more sense with your explanation , I was thinking it was just postitive 1 but I do see my mistake. Thank you

jjennylove  Jan 8, 2019

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