The equation y=58−x represents the temperature, y, in degrees Fahrenheit and the time, x, in hours from 6 p.m. to 9 a.m. on a certain day.

Let x = 0 represent the temperature at 6 p.m.

What is the average rate of change in temperature from 6 p.m. to 9 a.m.?

2°F per hour

−1°F per hour

−2°F per hour

1°F per hour

jjennylove Jan 8, 2019

#1**+2 **

Temp at 9 AM (15 hours form 6 PM) y = 58 - 15 = 43 degrees

Temp at 6 PM = y = 58-(0) = 58

(58-43) /( 6pm-9am) =

15/(0-15) = - 1 degree per hour (negative because the temperature is DROPPING from 6PM to 9 AM)

ElectricPavlov Jan 8, 2019

#2**+1 **

Oh okay that makes more sense with your explanation , I was thinking it was just postitive 1 but I do see my mistake. Thank you

jjennylove
Jan 8, 2019