The equation

24x2+25x−47

ax−2

=−8x−3−

53

ax−2

is true for all values of x≠

2

a

, where ais a constant.

What is the value of a?

A) -16

B) -3

C) 3

D) 16

Guest Dec 7, 2018

#1

#6**0 **

I understand that, BUT is THIS the equation you meant to post? (look carefully)

24x2+25x−47ax−2=−8x−3−53ax−2

ElectricPavlov
Dec 7, 2018

#5**-1 **

Do you mean...

\(24x^2+25x-47ax-2=-8x-3-53ax-2\) and it's true for all values of \(x\) that's not 2 , solve for \(a\) ? It's kind of hard with your format, but...

That equals \(24x^2+33x+6ax=0\) and we can factor this: \(x(24x+6a+33)=0\)

Since \(x\) is not 2, let's plug in 2 to see what we can exclude!

\(2(24\times 2+6a+33)=2(48+6a+33)=2(81+6a)\) and if that equals zero then \(a=-\frac{81}{6}\)

However, that's not one of the answer choices so none of the answer choices work.

That's what I think, but your formatting was not very clear, is it ok if you make it a bit neater? Thanks ;)

You are very welcome!

:P

CoolStuffYT Dec 7, 2018