the first option are A. 0.89 B. 0.45 C. 1.12
the second options are A. circular then elongated or B. elongated than circular
e = c / a
c = √[ a^2 - b^2 ] = √[80 - 16] = √64 = 8
a = √80 = 4√5
So
e = 8 / [ 4√5] = 2 / √5 ≈ .89
If the eccentricity is 0.....we have a circle...so.....the closer that the eccentricity is to 1, the more elongated it is
So....this ellipse is more elongated than circular
See here to confirm this, Jenny : https://www.desmos.com/calculator/sij3lqn4ts
As an addendum, note when we have this
x^2 y^2
___ + ____ = 1 ( A )
80 80
c = √[a^2 - b^2 ] = √[ 80^2 - 80^2 ] = √0 = 0
So
c / a = 0 / √80 = 0
But...notice that if we mutiplied ( A) through by 80 we get
x^2 + y^2 = 80
Which is a circle centered at the origin with a radius of √80
So.....the closer that e is to 0....the more circular
And the closer that e is to 1, the more elongated