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The formula db=20logS-26 approximately describes the relationship between of a sound in micropascals S and its reading on the decibel scale DB. if a bird singing produces a sound reading of about 400 uPa, and a jumbo jet produces a reading of 100 Pa, use the formula to convert these to their corresponding decibel values

Maltesewolfman  Aug 24, 2015

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 #1
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20log(400) - 26 = about 26 db  for the singing bird

 

For the second,  100Pa = 100,000,000 μPa...so we have

 

20log(100,000,000) - 26  = about 134 db

 

 

CPhill  Aug 24, 2015
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1+0 Answers

 #1
avatar+78557 
+10
Best Answer

20log(400) - 26 = about 26 db  for the singing bird

 

For the second,  100Pa = 100,000,000 μPa...so we have

 

20log(100,000,000) - 26  = about 134 db

 

 

CPhill  Aug 24, 2015

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