In the harbor a ferry boat is being pulled from one side to the other with a heavy cable. If another boat has to pass, the captain of the ferry lets the cable drop to the bottom of the canal. The cable hangs in the form of a parabola. The formula h = 0,02d^2 - 0,6d + 1 applies to one of the three situations above. In this formula d is the horizontal distance in metres from the left side of the quay h is the height in metres of the cable from the waterline.

a. Explain to which situation the formula h = 0,02d^2 - 0,6d + 1 applies.

b. Answer the same question for the formula h = 1/225 a^2 and - 30/225 a + 1 .

HeyxJacq Feb 28, 2019

#1**0 **

In the first scenario, h will be a positive number

in the second drawing h = 0

in the third scenario h will be some negative number

.02 d^2 - 0.6 d +1 will have a nadir (a low point) at -b/2a = - -0.6/(2*.02) = 15 m = d

SUstitute this value in for d .02(15^2) - 0.6(15) + 1 = h = = -3.5 so this applies to the third picture.

DO the same thing for this equation a (low point) = - b/ 2a = 15 (again)

now substitute this value into the equation and find h to see what scenario this second equation fits....... you can do it!

ElectricPavlov Feb 28, 2019

#1**0 **

Best Answer

In the first scenario, h will be a positive number

in the second drawing h = 0

in the third scenario h will be some negative number

.02 d^2 - 0.6 d +1 will have a nadir (a low point) at -b/2a = - -0.6/(2*.02) = 15 m = d

SUstitute this value in for d .02(15^2) - 0.6(15) + 1 = h = = -3.5 so this applies to the third picture.

DO the same thing for this equation a (low point) = - b/ 2a = 15 (again)

now substitute this value into the equation and find h to see what scenario this second equation fits....... you can do it!

ElectricPavlov Feb 28, 2019